Integrand size = 24, antiderivative size = 94 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^2} \, dx=\frac {3 \left (b^2-4 a c\right )^2 x}{64 c^3 d^2}+\frac {\left (b^2-4 a c\right )^3}{128 c^4 d^2 (b+2 c x)}-\frac {\left (b^2-4 a c\right ) (b+2 c x)^3}{128 c^4 d^2}+\frac {(b+2 c x)^5}{640 c^4 d^2} \]
[Out]
Time = 0.07 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.042, Rules used = {697} \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^2} \, dx=-\frac {\left (b^2-4 a c\right ) (b+2 c x)^3}{128 c^4 d^2}+\frac {\left (b^2-4 a c\right )^3}{128 c^4 d^2 (b+2 c x)}+\frac {3 x \left (b^2-4 a c\right )^2}{64 c^3 d^2}+\frac {(b+2 c x)^5}{640 c^4 d^2} \]
[In]
[Out]
Rule 697
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {3 \left (-b^2+4 a c\right )^2}{64 c^3 d^2}+\frac {\left (-b^2+4 a c\right )^3}{64 c^3 (b d+2 c d x)^2}+\frac {3 \left (-b^2+4 a c\right ) (b d+2 c d x)^2}{64 c^3 d^4}+\frac {(b d+2 c d x)^4}{64 c^3 d^6}\right ) \, dx \\ & = \frac {3 \left (b^2-4 a c\right )^2 x}{64 c^3 d^2}+\frac {\left (b^2-4 a c\right )^3}{128 c^4 d^2 (b+2 c x)}-\frac {\left (b^2-4 a c\right ) (b+2 c x)^3}{128 c^4 d^2}+\frac {(b+2 c x)^5}{640 c^4 d^2} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.07 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^2} \, dx=\frac {\frac {10 \left (b^4-12 a b^2 c+48 a^2 c^2\right ) x}{c^3}-\frac {20 b \left (b^2-12 a c\right ) x^2}{c^2}+\frac {40 \left (b^2+4 a c\right ) x^3}{c}+80 b x^4+32 c x^5+\frac {5 \left (b^2-4 a c\right )^3}{c^4 (b+2 c x)}}{640 d^2} \]
[In]
[Out]
Time = 2.65 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.80
method | result | size |
gosper | \(-\frac {-2 c^{3} x^{6}-6 b \,c^{2} x^{5}-10 a \,x^{4} c^{2}-5 b^{2} c \,x^{4}-20 a b c \,x^{3}-30 a^{2} c \,x^{2}+10 a^{3}}{20 \left (2 c x +b \right ) c \,d^{2}}\) | \(75\) |
parallelrisch | \(\frac {2 c^{3} x^{6}+6 b \,c^{2} x^{5}+10 a \,x^{4} c^{2}+5 b^{2} c \,x^{4}+20 a b c \,x^{3}+30 a^{2} c \,x^{2}-10 a^{3}}{20 c \,d^{2} \left (2 c x +b \right )}\) | \(75\) |
norman | \(\frac {\frac {a b \,x^{3}}{d}+\frac {a^{3} x}{b d}+\frac {c^{2} x^{6}}{10 d}+\frac {3 a^{2} x^{2}}{2 d}+\frac {\left (2 a c +b^{2}\right ) x^{4}}{4 d}+\frac {3 b c \,x^{5}}{10 d}}{d \left (2 c x +b \right )}\) | \(82\) |
default | \(\frac {\frac {\frac {16}{5} c^{4} x^{5}+8 b \,c^{3} x^{4}+16 x^{3} a \,c^{3}+4 b^{2} c^{2} x^{3}+24 a b \,c^{2} x^{2}-2 b^{3} c \,x^{2}+48 a^{2} c^{2} x -12 a \,b^{2} c x +b^{4} x}{64 c^{3}}-\frac {64 c^{3} a^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}}{128 c^{4} \left (2 c x +b \right )}}{d^{2}}\) | \(135\) |
risch | \(\frac {c \,x^{5}}{20 d^{2}}+\frac {b \,x^{4}}{8 d^{2}}+\frac {x^{3} a}{4 d^{2}}+\frac {b^{2} x^{3}}{16 c \,d^{2}}+\frac {3 a b \,x^{2}}{8 c \,d^{2}}-\frac {b^{3} x^{2}}{32 c^{2} d^{2}}+\frac {3 a^{2} x}{4 c \,d^{2}}-\frac {3 a \,b^{2} x}{16 c^{2} d^{2}}+\frac {b^{4} x}{64 c^{3} d^{2}}-\frac {a^{3}}{2 c \,d^{2} \left (2 c x +b \right )}+\frac {3 a^{2} b^{2}}{8 c^{2} d^{2} \left (2 c x +b \right )}-\frac {3 a \,b^{4}}{32 c^{3} d^{2} \left (2 c x +b \right )}+\frac {b^{6}}{128 c^{4} d^{2} \left (2 c x +b \right )}\) | \(187\) |
[In]
[Out]
none
Time = 0.59 (sec) , antiderivative size = 138, normalized size of antiderivative = 1.47 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^2} \, dx=\frac {64 \, c^{6} x^{6} + 192 \, b c^{5} x^{5} + 640 \, a b c^{4} x^{3} + 960 \, a^{2} c^{4} x^{2} + 5 \, b^{6} - 60 \, a b^{4} c + 240 \, a^{2} b^{2} c^{2} - 320 \, a^{3} c^{3} + 160 \, {\left (b^{2} c^{4} + 2 \, a c^{5}\right )} x^{4} + 10 \, {\left (b^{5} c - 12 \, a b^{3} c^{2} + 48 \, a^{2} b c^{3}\right )} x}{640 \, {\left (2 \, c^{5} d^{2} x + b c^{4} d^{2}\right )}} \]
[In]
[Out]
Time = 0.35 (sec) , antiderivative size = 160, normalized size of antiderivative = 1.70 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^2} \, dx=\frac {b x^{4}}{8 d^{2}} + \frac {c x^{5}}{20 d^{2}} + x^{3} \left (\frac {a}{4 d^{2}} + \frac {b^{2}}{16 c d^{2}}\right ) + x^{2} \cdot \left (\frac {3 a b}{8 c d^{2}} - \frac {b^{3}}{32 c^{2} d^{2}}\right ) + x \left (\frac {3 a^{2}}{4 c d^{2}} - \frac {3 a b^{2}}{16 c^{2} d^{2}} + \frac {b^{4}}{64 c^{3} d^{2}}\right ) + \frac {- 64 a^{3} c^{3} + 48 a^{2} b^{2} c^{2} - 12 a b^{4} c + b^{6}}{128 b c^{4} d^{2} + 256 c^{5} d^{2} x} \]
[In]
[Out]
none
Time = 0.20 (sec) , antiderivative size = 138, normalized size of antiderivative = 1.47 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^2} \, dx=\frac {b^{6} - 12 \, a b^{4} c + 48 \, a^{2} b^{2} c^{2} - 64 \, a^{3} c^{3}}{128 \, {\left (2 \, c^{5} d^{2} x + b c^{4} d^{2}\right )}} + \frac {16 \, c^{4} x^{5} + 40 \, b c^{3} x^{4} + 20 \, {\left (b^{2} c^{2} + 4 \, a c^{3}\right )} x^{3} - 10 \, {\left (b^{3} c - 12 \, a b c^{2}\right )} x^{2} + 5 \, {\left (b^{4} - 12 \, a b^{2} c + 48 \, a^{2} c^{2}\right )} x}{320 \, c^{3} d^{2}} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 221 vs. \(2 (86) = 172\).
Time = 0.29 (sec) , antiderivative size = 221, normalized size of antiderivative = 2.35 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^2} \, dx=\frac {{\left (\frac {15 \, b^{4} d^{4}}{{\left (2 \, c d x + b d\right )}^{4}} - \frac {120 \, a b^{2} c d^{4}}{{\left (2 \, c d x + b d\right )}^{4}} + \frac {240 \, a^{2} c^{2} d^{4}}{{\left (2 \, c d x + b d\right )}^{4}} - \frac {5 \, b^{2} d^{2}}{{\left (2 \, c d x + b d\right )}^{2}} + \frac {20 \, a c d^{2}}{{\left (2 \, c d x + b d\right )}^{2}} + 1\right )} {\left (2 \, c d x + b d\right )}^{5}}{640 \, c^{4} d^{7}} + \frac {\frac {b^{6} c^{5} d^{11}}{2 \, c d x + b d} - \frac {12 \, a b^{4} c^{6} d^{11}}{2 \, c d x + b d} + \frac {48 \, a^{2} b^{2} c^{7} d^{11}}{2 \, c d x + b d} - \frac {64 \, a^{3} c^{8} d^{11}}{2 \, c d x + b d}}{128 \, c^{9} d^{12}} \]
[In]
[Out]
Time = 9.95 (sec) , antiderivative size = 293, normalized size of antiderivative = 3.12 \[ \int \frac {\left (a+b x+c x^2\right )^3}{(b d+2 c d x)^2} \, dx=x^3\,\left (\frac {b^2+a\,c}{4\,c\,d^2}-\frac {3\,b^2}{16\,c\,d^2}\right )-x^2\,\left (\frac {b^3}{16\,c^2\,d^2}-\frac {b^3+6\,a\,c\,b}{8\,c^2\,d^2}+\frac {b\,\left (\frac {3\,\left (b^2+a\,c\right )}{4\,c\,d^2}-\frac {9\,b^2}{16\,c\,d^2}\right )}{2\,c}\right )+x\,\left (\frac {b\,\left (\frac {b^3}{8\,c^2\,d^2}-\frac {b^3+6\,a\,c\,b}{4\,c^2\,d^2}+\frac {b\,\left (\frac {3\,\left (b^2+a\,c\right )}{4\,c\,d^2}-\frac {9\,b^2}{16\,c\,d^2}\right )}{c}\right )}{c}-\frac {b^2\,\left (\frac {3\,\left (b^2+a\,c\right )}{4\,c\,d^2}-\frac {9\,b^2}{16\,c\,d^2}\right )}{4\,c^2}+\frac {3\,a\,\left (b^2+a\,c\right )}{4\,c^2\,d^2}\right )+\frac {-64\,a^3\,c^3+48\,a^2\,b^2\,c^2-12\,a\,b^4\,c+b^6}{2\,c\,\left (128\,x\,c^4\,d^2+64\,b\,c^3\,d^2\right )}+\frac {b\,x^4}{8\,d^2}+\frac {c\,x^5}{20\,d^2} \]
[In]
[Out]